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7x^2+400x-10000=0
a = 7; b = 400; c = -10000;
Δ = b2-4ac
Δ = 4002-4·7·(-10000)
Δ = 440000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{440000}=\sqrt{40000*11}=\sqrt{40000}*\sqrt{11}=200\sqrt{11}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(400)-200\sqrt{11}}{2*7}=\frac{-400-200\sqrt{11}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(400)+200\sqrt{11}}{2*7}=\frac{-400+200\sqrt{11}}{14} $
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